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Popular >

y= 1/(sqrt(x^2+1))

Solution

y = \frac{1}{x ^{2} + 1}

Solution

Domain : - \infty < x < \infty

Range : 0 < f (x) \leq 1

Y Intercepts : (0, 1)

Asymptotes : Horizontal y = 0

Extreme Points : Maximum (0, 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (0, 1]

Solution steps

Domain of

\frac{1}{x ^{2} + 1} : - \infty < x < \infty

Range of

\frac{1}{x ^{2} + 1} : 0 < f (x) \leq 1

Axis interception points of

\frac{1}{x ^{2} + 1} :

Y Intercepts

: (0, 1)

Asymptotes of

\frac{1}{x ^{2} + 1} :

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} + 1} :

Maximum

(0, 1)

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y = 2 e^{- x}

f(θ)=-cos^2(θ)

f (θ) = - cos^{2} (θ)

f(x)=x^3+8x^2+16x+7

f (x) = x^{3} + 8 x^{2} + 16 x + 7

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f (x) = \frac{x ^{2} + 4 x - 5}{2 x ^{5} - 6 x ^{4} + 4 x ^{2}}

y=x^{5/3}-5x^{2/3}

y = x^{\frac{5}{3}} - 5 x^{\frac{2}{3}}

Frequently Asked Questions (FAQ)

What is the y= 1/(sqrt(x^2+1)) ?
The y= 1/(sqrt(x^2+1)) is