What is the domain of f(x)=\sqrt[5]{-9t^4-3} ?

The domain of f(x)=\sqrt[5]{-9t^4-3} is -infinity <t<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=\sqrt[5]{-9t^4-3}

domain

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

y = 0.4 x + 8, (- 5, 12)

f (x) = \frac{1}{3} x^{3}

f (x) = 5 x - 2 y = 10

(- 1, - 9), (5, 9)

f (x) = - e^{x}

What is the domain of f(x)=\sqrt[5]{-9t^4-3} ?
The domain of f(x)=\sqrt[5]{-9t^4-3} is -infinity <t<infinity