What is the inverse of f(x)=-3(x-1)^2+4 ?

The inverse of f(x)=-3(x-1)^2+4 is sqrt(-(x-4)/3)+1,-sqrt(-(x-4)/3)+1

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inverse of f(x)=-3(x-1)^2+4

inverse

f (x) = - 3 (x - 1)^{2} + 4

- \frac{x - 4}{3} + 1, - - \frac{x - 4}{3} + 1

Solution steps

y = - 3 (x - 1)^{2} + 4

Replace

x

with

y

x = - 3 (y - 1)^{2} + 4

Solve for

y, x = - 3 (y - 1)^{2} + 4

- \frac{x - 4}{3} + 1, - - \frac{x - 4}{3} + 1

(- 11, 15), (9, - 12)

f (x) = e^{x - 2} - 3

f (x) = 3^{- x}

f (x) = \frac{x ^{2} + 4}{x}

y = \frac{3}{4} x + 3, (3, - 3)

What is the inverse of f(x)=-3(x-1)^2+4 ?
The inverse of f(x)=-3(x-1)^2+4 is sqrt(-(x-4)/3)+1,-sqrt(-(x-4)/3)+1