What is the domain of sqrt((6x-4)^{1/2)} ?

The domain of sqrt((6x-4)^{1/2)} is x>= 2/3

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domain of sqrt((6x-4)^{1/2)}

domain

(6 x - 4)^{\frac{1}{2}}

x \geq \frac{2}{3}

Interval Notation

[\frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{2}{3}

The function domain

x \geq \frac{2}{3}

x^{4} - 32 x^{2} + 5

f (x) = \frac{2}{x ^{\frac{1}{3}}} - 2

f (x) = \frac{1}{1 - x} + 1

f (x) = - 4 x + 3

f (x) = x^{2} + 3

What is the domain of sqrt((6x-4)^{1/2)} ?
The domain of sqrt((6x-4)^{1/2)} is x>= 2/3