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Popular >

f(x)=(-2x^2-2x)/(x^2-3x-4)

Solution

f (x) = \frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4}

Solution

Domain : x < - 1 or - 1 < x < 4 or x > 4

Range : f (x) < - 2 or - 2 < f (x) < - \frac{2}{5} or f (x) > - \frac{2}{5}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = 4, Horizontal y = - 2

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 4) \cup (4, \infty)

Range : (- \infty, - 2) \cup (- 2, - \frac{2}{5}) \cup (- \frac{2}{5}, \infty)

Solution steps

Domain of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} : x < - 1 or - 1 < x < 4 or x > 4

Range of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} : f (x) < - 2 or - 2 < f (x) < - \frac{2}{5} or f (x) > - \frac{2}{5}

Axis interception points of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} :

Vertical

: x = 4,

Horizontal

: y = - 2

Extreme Points of

\frac{- 2 x ^{2} - 2 x}{x ^{2} - 3 x - 4} :

None

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Frequently Asked Questions (FAQ)

What is the f(x)=(-2x^2-2x)/(x^2-3x-4) ?
The f(x)=(-2x^2-2x)/(x^2-3x-4) is