What is the f(x)=sqrt((x^3-3x^2+x-3)/(3x+1)) ?

The f(x)=sqrt((x^3-3x^2+x-3)/(3x+1)) is

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f(x)=sqrt((x^3-3x^2+x-3)/(3x+1))

f (x) = \frac{x ^{3} - 3 x ^{2} + x - 3}{3 x + 1}

Domain : x < - \frac{1}{3} or x \geq 3

X Intercepts : (3, 0)

Asymptotes : None

Extreme Points : Minimum (3, 0)

Solution steps

Domain of

\frac{x ^{3} - 3 x ^{2} + x - 3}{3 x + 1} : x < - \frac{1}{3} or x \geq 3

Axis interception points of

\frac{x ^{3} - 3 x ^{2} + x - 3}{3 x + 1} :

X Intercepts

: (3, 0)

Asymptotes of

\frac{x ^{3} - 3 x ^{2} + x - 3}{3 x + 1} :

None

Extreme Points of

\frac{x ^{3} - 3 x ^{2} + x - 3}{3 x + 1} :

Minimum

(3, 0)

f (x) = ln (ln^{2} (x))

f (x) = \frac{- 3 x ^{2} - 12 x - 9}{x ^{2} + 5 x + 4}

f (x) = sin (5 x) cos (3 x)

f (x) = sin (3 x^{2} - 2)

f (θ) = cos (2 θ) + cos (4 θ)

What is the f(x)=sqrt((x^3-3x^2+x-3)/(3x+1)) ?
The f(x)=sqrt((x^3-3x^2+x-3)/(3x+1)) is