What is the domain of f(x)=4(sqrt(x-3))-1 ?

The domain of f(x)=4(sqrt(x-3))-1 is x>= 3

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domain of f(x)=4(sqrt(x-3))-1

domain

f (x) = 4 (x - 3) - 1

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

y = \frac{4}{7} x + 5, (4, - 7)

f (x) = x^{2} + 2 x + 7

y = arcsin (x)

f (x) = - (x + 2)^{2} + 6

f (x) = - 4

What is the domain of f(x)=4(sqrt(x-3))-1 ?
The domain of f(x)=4(sqrt(x-3))-1 is x>= 3