What is the monotone (9x)/(16-x^2) ?

The monotone (9x)/(16-x^2) is Increasing:-infinity <x<-4,Increasing:-4<x<4,Increasing:4<x<infinity

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monotone (9x)/(16-x^2)

monotone intervals

\frac{9 x}{16 - x ^{2}}

Increasing : - \infty < x < - 4, Increasing : - 4 < x < 4, Increasing : 4 < x < \infty

Solution steps

f^{'} (x) = \frac{9 ( 16 + x ^{2} )}{( 16 - x ^{2} ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 4,

Increasing

: 4 < x < \infty

Increasing : - \infty < x < - 4, Increasing : - 4 < x < 4, Increasing : 4 < x < \infty

f (x) = x^{2} - 11, x \geq 0

f (x) = - 6 x + 3

f (x) = - x^{2} + 9

5 x^{2} - 48 x + 20

What is the monotone (9x)/(16-x^2) ?
The monotone (9x)/(16-x^2) is Increasing:-infinity <x<-4,Increasing:-4<x<4,Increasing:4<x<infinity