What is the y=((x+1)(x+2)(x+1))/((x^2+3x+2)) ?

The y=((x+1)(x+2)(x+1))/((x^2+3x+2)) is

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y=((x+1)(x+2)(x+1))/((x^2+3x+2))

y = \frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{( x ^{2} + 3 x + 2 )}

Domain : x < - 2 or - 2 < x < - 1 or x > - 1

Range : f (x) < - 1 or - 1 < f (x) < 0 or f (x) > 0

Y Intercepts : (0, 1)

Asymptotes : Slant y = x + 1

Extreme Points : None

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Range : (- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{x ^{2} + 3 x + 2} : x < - 2 or - 2 < x < - 1 or x > - 1

Range of

\frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{x ^{2} + 3 x + 2} : f (x) < - 1 or - 1 < f (x) < 0 or f (x) > 0

Axis interception points of

\frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{x ^{2} + 3 x + 2} :

Y Intercepts

: (0, 1)

Asymptotes of

\frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{x ^{2} + 3 x + 2} :

Slant

: y = x + 1

Extreme Points of

\frac{( x + 1 ) ( x + 2 ) ( x + 1 )}{x ^{2} + 3 x + 2} :

None

f (x) = x^{2} - 7 x + 13

y = - 4 x + 11

ln (\frac{x ^{2} - 1}{x ^{5}}), x > 1

f (x) = 2 ln (x + 2)

f (x) = x^{4} - 8 x^{2} + 12

What is the y=((x+1)(x+2)(x+1))/((x^2+3x+2)) ?
The y=((x+1)(x+2)(x+1))/((x^2+3x+2)) is