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Popular >

distance (-2,5),(0,1)

Solution

distance

(- 2, 5), (0, 1)

Solution

25

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 5)

and

(0, 1)

is

= (0 - (- 2))^{2} + (1 - 5)^{2}

Simplify

= 25

Popular Examples

inverse of f(x)=(e^x)/(1+2e^x)inverse

f (x) = \frac{e ^{x}}{1 + 2 e ^{x}}

intercepts of f(x)=(8x)/(0.3x^2+4.1)-0.1 intercepts

f (x) = \frac{8 x}{0.3 x ^{2} + 4.1} - 0.1

inverse of f(x)=-x^2+1 inverse

f (x) = - x^{2} + 1

domain of f(x)=sqrt(x^2+4)domain

f (x) = x^{2} + 4

range of sqrt(5-x)range

5 - x

Frequently Asked Questions (FAQ)

What is the distance (-2,5),(0,1) ?
The distance (-2,5),(0,1) is 2sqrt(5)