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midpoint
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inverse of f(x)=((1+x^2))/((2+x^4))inverse parity (cos(9x))^xparity inverse of f(x)=(5)^xinverse critical f(x)=x^3+x^2+xcritical points intercepts of y=-5x+6intercepts
Frequently Asked Questions (FAQ)
What is the midpoint (8,-8.5),(8,-6) ?
The midpoint (8,-8.5),(8,-6) is (8,-7.25)