What is the periodicity of f(x)=x[n]=5sin(0.2pin) ?

The periodicity of f(x)=x[n]=5sin(0.2pin) is 10

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periodicity of f(x)=x[n]=5sin(0.2pin)

periodicity

f (x) = x [n] = 5 sin (0.2 πn)

10

Solution steps

Periodicity of

a \cdot sin (b x + c) + d = \frac{periodicity of sin ( x )}{∣ b ∣}

Periodicity of

sin (x)

2 π

= \frac{2 π}{∣ 0.62831 \dots ∣}

Simplify

= 10

f (x) = x^{3} - 2

x - 6 - 6

f (x) = - 2 sin (x)

f (x) = 1 - (x - 2)^{2}

4 x - 2 y = 18

What is the periodicity of f(x)=x[n]=5sin(0.2pin) ?
The periodicity of f(x)=x[n]=5sin(0.2pin) is 10