What is the extreme f(x)=-2sin(x) ?

The extreme f(x)=-2sin(x) is Minimum(pi/2+2pin,-2),Maximum((3pi)/2+2pin,2)

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extreme f(x)=-2sin(x)

extreme points

f (x) = - 2 sin (x)

Minimum (\frac{π}{2} + 2 πn, - 2), Maximum (\frac{3 π}{2} + 2 πn, 2)

Solution steps

Find the critical points:

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Domain of

- 2 sin (x) : - \infty < x < \infty

Find intervals:

Decreasing

: 2 πn \leq x < \frac{π}{2} + 2 πn,

Increasing

: \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn,

Decreasing

: \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = \frac{π}{2} + 2 πn

into

- 2 sin (x) \Rightarrow y = - 2

Minimum (\frac{π}{2} + 2 πn, - 2)

Plug the extreme point

x = \frac{3 π}{2} + 2 πn

into

- 2 sin (x) \Rightarrow y = 2

Maximum (\frac{3 π}{2} + 2 πn, 2)

Minimum (\frac{π}{2} + 2 πn, - 2), Maximum (\frac{3 π}{2} + 2 πn, 2)

f (x) = 1 - (x - 2)^{2}

4 x - 2 y = 18

\frac{x ^{2} + x - 12}{x - 3}

y + 1 = 2 x

f (x) = x + 13

What is the extreme f(x)=-2sin(x) ?
The extreme f(x)=-2sin(x) is Minimum(pi/2+2pin,-2),Maximum((3pi)/2+2pin,2)