What is the inverse of f(x)=(x-1)/((x+2)) ?

The inverse of f(x)=(x-1)/((x+2)) is (-1-2x)/(x-1)

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inverse of f(x)=(x-1)/((x+2))

inverse

f (x) = \frac{x - 1}{( x + 2 )}

\frac{- 1 - 2 x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 2}

Replace

x

with

y

x = \frac{y - 1}{y + 2}

Solve for

y, x = \frac{y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 1}

f (x) = 3 x - 2

(9, 3), (5, - 4)

f (x) = \frac{x + 4}{x ^{2} + 3 x + 2}

x^{2} + 3

f (x) = \frac{3}{x + 8}

What is the inverse of f(x)=(x-1)/((x+2)) ?
The inverse of f(x)=(x-1)/((x+2)) is (-1-2x)/(x-1)