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Popular >

range of y=x^2+1

Solution

range

y = x^{2} + 1

Solution

f (x) \geq 1

+1

Interval Notation

[1, \infty)

Solution steps

Vertex of

x^{2} + 1 :

Minimum

(0, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, 1)

f (x) \geq 1

Popular Examples

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extreme f(x)=x^2(x+3)extreme points

f (x) = x^{2} (x + 3)

inverse of ln((s-2)/(s+2))inverse

ln (\frac{s - 2}{s + 2})

domain of f(x)=\sqrt[3]{t-3}domain

Frequently Asked Questions (FAQ)

What is the range of y=x^2+1 ?
The range of y=x^2+1 is f(x)>= 1