What is the inverse of f(x)=(3x-1)/(x+2) ?

The inverse of f(x)=(3x-1)/(x+2) is (-1-2x)/(x-3)

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inverse of f(x)=(3x-1)/(x+2)

inverse

f (x) = \frac{3 x - 1}{x + 2}

\frac{- 1 - 2 x}{x - 3}

Solution steps

y = \frac{3 x - 1}{x + 2}

Replace

x

with

y

x = \frac{3 y - 1}{y + 2}

Solve for

y, x = \frac{3 y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 3}

f (x) = e^{1 - 4 x^{- 3}}

f (x) = \frac{x - 2}{2 x + 3}

f (x) = \frac{x ^{2} + 1}{x ^{2} + 3}

f (x) = 6 (x - 5)

f (x) = 2 (x + 3)^{2} - 5

What is the inverse of f(x)=(3x-1)/(x+2) ?
The inverse of f(x)=(3x-1)/(x+2) is (-1-2x)/(x-3)