What is the inverse of f(x)=2(x+3)^2-5 ?

The inverse of f(x)=2(x+3)^2-5 is sqrt((x+5)/2)-3,-sqrt((x+5)/2)-3

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inverse of f(x)=2(x+3)^2-5

inverse

f (x) = 2 (x + 3)^{2} - 5

\frac{x + 5}{2} - 3, - \frac{x + 5}{2} - 3

Solution steps

y = 2 (x + 3)^{2} - 5

Replace

x

with

y

x = 2 (y + 3)^{2} - 5

Solve for

y, x = 2 (y + 3)^{2} - 5

\frac{x + 5}{2} - 3, - \frac{x + 5}{2} - 3

f (x) = \frac{ln ( 3 x )}{8 + ln ( 3 x )}

f (x) = 9 sin (x - 5) + 8

f (x) = \frac{2 x - 6}{4}

f (x) = x^{2} - 12 x + 11

f (x) = \frac{2 x + 1}{4 x - 1}

What is the inverse of f(x)=2(x+3)^2-5 ?
The inverse of f(x)=2(x+3)^2-5 is sqrt((x+5)/2)-3,-sqrt((x+5)/2)-3