What is the inverse of f(x)=(3-2x)/(3x+b) ?

The inverse of f(x)=(3-2x)/(3x+b) is (3-bx)/(3x+2)

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inverse of f(x)=(3-2x)/(3x+b)

inverse

f (x) = \frac{3 - 2 x}{3 x + b}

\frac{3 - b x}{3 x + 2}

Solution steps

y = \frac{3 - 2 x}{3 x + b}

Replace

x

with

y

x = \frac{3 - 2 y}{3 y + b}

Solve for

y, x = \frac{3 - 2 y}{3 y + b}

\frac{3 - b x}{3 x + 2}

ln (2 x - 3) - ln (x + 5) + 1

f (x) = \frac{3 x + 1}{4 x - 2}

f (x) = 5 (x + 3)^{3} - 2

f (x) = \frac{2 x}{3 x + 7}

f (x) = 3^{x + 2} - 1

What is the inverse of f(x)=(3-2x)/(3x+b) ?
The inverse of f(x)=(3-2x)/(3x+b) is (3-bx)/(3x+2)