What is the inverse of f(x)=(x^2-1)/4 ?

The inverse of f(x)=(x^2-1)/4 is sqrt(4x+1),-sqrt(4x+1)

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inverse of f(x)=(x^2-1)/4

inverse

f (x) = \frac{x ^{2} - 1}{4}

4 x + 1, - 4 x + 1

Solution steps

y = \frac{x ^{2} - 1}{4}

Replace

x

with

y

x = \frac{y ^{2} - 1}{4}

Solve for

y, x = \frac{y ^{2} - 1}{4}

4 x + 1, - 4 x + 1

f (x) = - x + 6

f (x) = x^{2} + 16

f (x) = \frac{( 2 x - 3 )}{5 x - 7}

f (x) = 3 + 2 x + x^{2}

What is the inverse of f(x)=(x^2-1)/4 ?
The inverse of f(x)=(x^2-1)/4 is sqrt(4x+1),-sqrt(4x+1)