What is the inverse of f(x)=(x-5)^2+9 ?

The inverse of f(x)=(x-5)^2+9 is sqrt(x-9)+5,-sqrt(x-9)+5

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inverse of f(x)=(x-5)^2+9

inverse

f (x) = (x - 5)^{2} + 9

x - 9 + 5, - x - 9 + 5

Solution steps

y = (x - 5)^{2} + 9

Replace

x

with

y

x = (y - 5)^{2} + 9

Solve for

y, x = (y - 5)^{2} + 9

x - 9 + 5, - x - 9 + 5

f (x) = e^{x} - 2

f (x) = 3 x^{2} + 2, x \geq 0

f (x) = e^{x - 5}

y = arcsec (x)

f (x) = - \frac{3}{x + 1} - 3

What is the inverse of f(x)=(x-5)^2+9 ?
The inverse of f(x)=(x-5)^2+9 is sqrt(x-9)+5,-sqrt(x-9)+5