What is the inverse of f(x)=log_{10}((x+4)/2)-3 ?

The inverse of f(x)=log_{10}((x+4)/2)-3 is 5^{x+3}*2^{x+4}-4

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inverse of f(x)=log_{10}((x+4)/2)-3

inverse

f (x) = lo g_{10} (\frac{x + 4}{2}) - 3

5^{x + 3} \cdot 2^{x + 4} - 4

Solution steps

y = lo g_{10} (\frac{x + 4}{2}) - 3

Replace

x

with

y

x = lo g_{10} (\frac{y + 4}{2}) - 3

Solve for

y, x = lo g_{10} (\frac{y + 4}{2}) - 3

5^{x + 3} \cdot 2^{x + 4} - 4

y = x^{2} - 6 x + 8

f (x) = \frac{2 x - 1}{3 - 4 x}

f (x) = (3 x^{3} + 2)^{\frac{1}{5}}

f (x) = \frac{2 x + 1}{x - 2}

What is the inverse of f(x)=log_{10}((x+4)/2)-3 ?
The inverse of f(x)=log_{10}((x+4)/2)-3 is 5^{x+3}*2^{x+4}-4