What is the inverse of f(x)= 1/(e^{x^2)+3} ?

The inverse of f(x)= 1/(e^{x^2)+3} is sqrt(ln(1/x-3)),-sqrt(ln(1/x-3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/(e^{x^2)+3}

inverse

f (x) = \frac{1}{e ^{x^{2}} + 3}

ln (\frac{1}{x} - 3), - ln (\frac{1}{x} - 3)

Solution steps

y = \frac{1}{e ^{x^{2}} + 3}

Replace

x

with

y

x = \frac{1}{e ^{y^{2}} + 3}

Solve for

y, x = \frac{1}{e ^{y^{2}} + 3}

ln (\frac{1}{x} - 3), - ln (\frac{1}{x} - 3)

f (x) = \frac{2}{x} + 2

f (x) = \frac{7 + 3 x}{5 x + 6}

sin (6 x)

f (x) = 3 x^{2} - 9

f (x) = \frac{3 x + 8}{4 x + 5}

What is the inverse of f(x)= 1/(e^{x^2)+3} ?
The inverse of f(x)= 1/(e^{x^2)+3} is sqrt(ln(1/x-3)),-sqrt(ln(1/x-3))