What is the inverse of f(x)=sin(x^2) ?

The inverse of f(x)=sin(x^2) is sqrt(arcsin(x)),-sqrt(arcsin(x))

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inverse of f(x)=sin(x^2)

inverse

f (x) = sin (x^{2})

arcsin (x), - arcsin (x)

Solution steps

sin (a) = b \Rightarrow a = arcsin (b)

x^{2} = arcsin (y)

Solve for

x, x^{2} = arcsin (y)

arcsin (y), - arcsin (y)

Substitute

y = x

arcsin (x), - arcsin (x)

\frac{8}{x - 2}

f (x) = \frac{x ^{2}}{4}

f (x) = 3^{x + 2} + 1

h (x) = 8 x - 12

f (x) = \frac{5}{x - 4}

What is the inverse of f(x)=sin(x^2) ?
The inverse of f(x)=sin(x^2) is sqrt(arcsin(x)),-sqrt(arcsin(x))