What is the inverse of f(x)=(x-1)^2-4 ?

The inverse of f(x)=(x-1)^2-4 is sqrt(x+4)+1,-sqrt(x+4)+1

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inverse of f(x)=(x-1)^2-4

inverse

f (x) = (x - 1)^{2} - 4

x + 4 + 1, - x + 4 + 1

Solution steps

y = (x - 1)^{2} - 4

Replace

x

with

y

x = (y - 1)^{2} - 4

Solve for

y, x = (y - 1)^{2} - 4

x + 4 + 1, - x + 4 + 1

f (x) = \frac{x - 2}{3 x + 4}

f (x) = \frac{x ^{2} - 9}{4}

lo g_{2} (k x - 12)

f (x) = \frac{2 x + 3}{x - 2}

f (x) = \frac{2 x + 3}{7 x + 4}

What is the inverse of f(x)=(x-1)^2-4 ?
The inverse of f(x)=(x-1)^2-4 is sqrt(x+4)+1,-sqrt(x+4)+1