What is the inverse of f(x)=9x+sqrt(x+82) ?

The inverse of f(x)=9x+sqrt(x+82) is (18x+1+sqrt(36x+26569))/(162),(18x+1-sqrt(36x+26569))/(162)

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inverse of f(x)=9x+sqrt(x+82)

inverse

f (x) = 9 x + x + 82

\frac{18 x + 1 + 36 x + 26569}{162}, \frac{18 x + 1 - 36 x + 26569}{162}

Solution steps

y = 9 x + x + 82

Replace

x

with

y

x = 9 y + y + 82

Solve for

y, x = 9 y + y + 82

\frac{18 x + 1 + 36 x + 26569}{162}, \frac{18 x + 1 - 36 x + 26569}{162}

f (x) = 3 (x + 2)^{2} - 5, x \leq - 2

f (x) = (x + 4)^{2} - 3

f (x) = 4 x - 9

f (x) = \frac{5 x - 2}{4 - 5 x}

f (x) = \frac{x}{9 + x ^{2}}

What is the inverse of f(x)=9x+sqrt(x+82) ?
The inverse of f(x)=9x+sqrt(x+82) is (18x+1+sqrt(36x+26569))/(162),(18x+1-sqrt(36x+26569))/(162)