What is the inverse of e^{1-4x^{-3}} ?

The inverse of e^{1-4x^{-3}} is -\sqrt[3]{4/(ln(x)-1)}

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inverse of e^{1-4x^{-3}}

inverse

e^{1 - 4 x^{- 3}}

Solution steps

y = e^{1 - 4 x^{- 3}}

Replace

x

with

y

x = e^{1 - 4 y^{- 3}}

Solve for

y, x = e^{1 - 4 y^{- 3}}

y = - x + 5

(x^{2} + 5 x)^{\frac{1}{2}}

f (x) = 1 - 2 + x

f (x) = 5 e^{x - 2} + 6

f (x) = (x + \frac{1}{2})^{2} - \frac{9}{4}

What is the inverse of e^{1-4x^{-3}} ?
The inverse of e^{1-4x^{-3}} is -\sqrt[3]{4/(ln(x)-1)}