What is the inverse of f(x)=3(x+5)^2-4,x<=-5 ?

The inverse of f(x)=3(x+5)^2-4,x<=-5 is sqrt((x+4)/3)-5,-sqrt((x+4)/3)-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3(x+5)^2-4,x<=-5

inverse

f (x) = 3 (x + 5)^{2} - 4, x \leq - 5

\frac{x + 4}{3} - 5, - \frac{x + 4}{3} - 5

Solution steps

y = 3 (x + 5)^{2} - 4

Replace

x

with

y

x = 3 (y + 5)^{2} - 4

Solve for

y, x = 3 (y + 5)^{2} - 4

\frac{x + 4}{3} - 5, - \frac{x + 4}{3} - 5

\frac{8}{e ^{x - 3} + 6}

[2]

f (x) = - x^{3} + 5

25 - x^{2}

f (x) = \frac{7}{7 - 5 x}

What is the inverse of f(x)=3(x+5)^2-4,x<=-5 ?
The inverse of f(x)=3(x+5)^2-4,x<=-5 is sqrt((x+4)/3)-5,-sqrt((x+4)/3)-5