What is the inverse of 3(1/4)^{x-2}+4 ?

The inverse of 3(1/4)^{x-2}+4 is -(ln((x-4)/3))/(2ln(2))+2

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inverse of 3(1/4)^{x-2}+4

inverse

3 (\frac{1}{4})^{x - 2} + 4

- \frac{ln ( \frac{x - 4}{3} )}{2 ln ( 2 )} + 2

Solution steps

y = 3 (\frac{1}{4})^{x - 2} + 4

Replace

x

with

y

x = 3 (\frac{1}{4})^{y - 2} + 4

Solve for

y, x = 3 (\frac{1}{4})^{y - 2} + 4

- \frac{ln ( \frac{x - 4}{3} )}{2 ln ( 2 )} + 2

f (x) = x^{2} + x, x \geq - \frac{1}{2}

4 t^{2} + 1

f (x) = \frac{x ^{3} + 2}{x ^{3} - 2}

f (x) = \frac{2}{2 x - 1}

y = \frac{x + 1}{2 x + 1}

What is the inverse of 3(1/4)^{x-2}+4 ?
The inverse of 3(1/4)^{x-2}+4 is -(ln((x-4)/3))/(2ln(2))+2