What is the inverse of f(x)=-4x^2-5 ?

The inverse of f(x)=-4x^2-5 is sqrt(-(x+5)/4),-sqrt(-(x+5)/4)

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inverse of f(x)=-4x^2-5

inverse

f (x) = - 4 x^{2} - 5

- \frac{x + 5}{4}, - - \frac{x + 5}{4}

Solution steps

y = - 4 x^{2} - 5

Replace

x

with

y

x = - 4 y^{2} - 5

Solve for

y, x = - 4 y^{2} - 5

- \frac{x + 5}{4}, - - \frac{x + 5}{4}

9 sin (x - 5) + 8

f (x) = 2 x^{2} - 3 x - 1

e^{x} - 3

f (x) = \frac{x}{2 x ^{2} - x - 1}

f (x) = 2 x^{2} - 6 x + 13

What is the inverse of f(x)=-4x^2-5 ?
The inverse of f(x)=-4x^2-5 is sqrt(-(x+5)/4),-sqrt(-(x+5)/4)