What is the inverse of f(x)=(4-3x)/(7-9x) ?

The inverse of f(x)=(4-3x)/(7-9x) is (4-7x)/(3(1-3x))

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inverse of f(x)=(4-3x)/(7-9x)

inverse

f (x) = \frac{4 - 3 x}{7 - 9 x}

\frac{4 - 7 x}{3 ( 1 - 3 x )}

Solution steps

y = \frac{4 - 3 x}{7 - 9 x}

Replace

x

with

y

x = \frac{4 - 3 y}{7 - 9 y}

Solve for

y, x = \frac{4 - 3 y}{7 - 9 y}

\frac{4 - 7 x}{3 ( 1 - 3 x )}

f (x) = (x^{\frac{1}{5}} - 7)^{7}

f (x) = \frac{x}{2 x - 6}

g (x) = lo g_{3} (x)

f (x) = x - 4 + 2

f (x) = - 8 x + 24

What is the inverse of f(x)=(4-3x)/(7-9x) ?
The inverse of f(x)=(4-3x)/(7-9x) is (4-7x)/(3(1-3x))