What is the inverse of f(x)=(x-9)^2+1 ?

The inverse of f(x)=(x-9)^2+1 is sqrt(x-1)+9,-sqrt(x-1)+9

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inverse of f(x)=(x-9)^2+1

inverse

f (x) = (x - 9)^{2} + 1

x - 1 + 9, - x - 1 + 9

Solution steps

y = (x - 9)^{2} + 1

Replace

x

with

y

x = (y - 9)^{2} + 1

Solve for

y, x = (y - 9)^{2} + 1

x - 1 + 9, - x - 1 + 9

f (x) = (x - 2)^{2} - 3

x^{2} + 4 x + 3

f (5) = ln (3 x - 5) - ln (x + 9) + 5

f (x) = x^{2} + x, x \geq \frac{1}{2}

7 x + 4

What is the inverse of f(x)=(x-9)^2+1 ?
The inverse of f(x)=(x-9)^2+1 is sqrt(x-1)+9,-sqrt(x-1)+9