What is the inverse of f(x)=4x^2-9 ?

The inverse of f(x)=4x^2-9 is (sqrt(x+9))/2 ,-(sqrt(x+9))/2

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inverse of f(x)=4x^2-9

inverse

f (x) = 4 x^{2} - 9

\frac{x + 9}{2}, - \frac{x + 9}{2}

Solution steps

y = 4 x^{2} - 9

Replace

x

with

y

x = 4 y^{2} - 9

Solve for

y, x = 4 y^{2} - 9

\frac{x + 9}{2}, - \frac{x + 9}{2}

f (x) = 5 x^{- \frac{4}{3}}

f (x) = \frac{x + 1}{x - 1}

f (x) = \frac{1}{x ^{2} + x - 12}

f (x) = \frac{x + 5}{7}

\frac{2}{3 x - 5}

What is the inverse of f(x)=4x^2-9 ?
The inverse of f(x)=4x^2-9 is (sqrt(x+9))/2 ,-(sqrt(x+9))/2