What is the inverse of f(x)=(x-3)^2-2 ?

The inverse of f(x)=(x-3)^2-2 is sqrt(x+2)+3,-sqrt(x+2)+3

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inverse of f(x)=(x-3)^2-2

inverse

f (x) = (x - 3)^{2} - 2

x + 2 + 3, - x + 2 + 3

Solution steps

y = (x - 3)^{2} - 2

Replace

x

with

y

x = (y - 3)^{2} - 2

Solve for

y, x = (y - 3)^{2} - 2

x + 2 + 3, - x + 2 + 3

f (x) = (x + 10)^{3}

w (t) = 80 - 2.5 t

2 \cdot 3^{x} + 9^{x} + 5

- 2 + ln (x)

h (c) = 2 c + 2

What is the inverse of f(x)=(x-3)^2-2 ?
The inverse of f(x)=(x-3)^2-2 is sqrt(x+2)+3,-sqrt(x+2)+3