What is the inverse of 5y+4=(x+3)^2+1/2 ?

The inverse of 5y+4=(x+3)^2+1/2 is sqrt((2x-1)/2)-3,-sqrt((2x-1)/2)-3

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inverse of 5y+4=(x+3)^2+1/2

inverse

5 y + 4 = (x + 3)^{2} + \frac{1}{2}

\frac{2 x - 1}{2} - 3, - \frac{2 x - 1}{2} - 3

Solution steps

y = (x + 3)^{2} + \frac{1}{2}

Replace

x

with

y

x = (y + 3)^{2} + \frac{1}{2}

Solve for

y, x = (y + 3)^{2} + \frac{1}{2}

\frac{2 x - 1}{2} - 3, - \frac{2 x - 1}{2} - 3

6 - x

f (x) = cos^{2} (x)

x^{2} + 4 x - 2

What is the inverse of 5y+4=(x+3)^2+1/2 ?
The inverse of 5y+4=(x+3)^2+1/2 is sqrt((2x-1)/2)-3,-sqrt((2x-1)/2)-3