What is the inverse of f(x)=\sqrt[3]{x-7}+2 ?

The inverse of f(x)=\sqrt[3]{x-7}+2 is x^3-6x^2+12x-1

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inverse of f(x)=\sqrt[3]{x-7}+2

inverse

x^{3} - 6 x^{2} + 12 x - 1

Solution steps

Replace

x

with

y

Solve for

x^{3} - 6 x^{2} + 12 x - 1

f (x) = cos^{2} (x)

x^{2} + 4 x - 2

f (x) = e^{2 x} - 1

f (x) = 2 (x - 1)^{2} - 3

f (x) = 4 (x - 3)^{2} + 2

What is the inverse of f(x)=\sqrt[3]{x-7}+2 ?
The inverse of f(x)=\sqrt[3]{x-7}+2 is x^3-6x^2+12x-1