What is the inverse of f(x)=(2x^2+3)/5 ?

The inverse of f(x)=(2x^2+3)/5 is sqrt((5x-3)/2),-sqrt((5x-3)/2)

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inverse of f(x)=(2x^2+3)/5

inverse

f (x) = \frac{2 x ^{2} + 3}{5}

\frac{5 x - 3}{2}, - \frac{5 x - 3}{2}

Solution steps

y = \frac{2 x ^{2} + 3}{5}

Replace

x

with

y

x = \frac{2 y ^{2} + 3}{5}

Solve for

y, x = \frac{2 y ^{2} + 3}{5}

\frac{5 x - 3}{2}, - \frac{5 x - 3}{2}

2 \cdot 3^{x} + 9^{x} + 3

p (x) = x^{2} + 1

f (x) = \frac{x ^{2} + 3}{2 x - 5}

f (x) = \frac{3}{2}

What is the inverse of f(x)=(2x^2+3)/5 ?
The inverse of f(x)=(2x^2+3)/5 is sqrt((5x-3)/2),-sqrt((5x-3)/2)