What is the inverse of f(x)=(x-16)^2 ?

The inverse of f(x)=(x-16)^2 is sqrt(x)+16,-sqrt(x)+16

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inverse of f(x)=(x-16)^2

inverse

f (x) = (x - 16)^{2}

x + 16, - x + 16

Solution steps

y = (x - 16)^{2}

Replace

x

with

y

x = (y - 16)^{2}

Solve for

y, x = (y - 16)^{2}

x + 16, - x + 16

f (x) = (5 x)^{- \frac{4}{3}}

y = ln (2 x - 3) - ln (x + 5) + 1

f (x) = 1 + 4 + 8 x

f (x) = \frac{1}{x ^{3}} + 4

- 2 x + 6

What is the inverse of f(x)=(x-16)^2 ?
The inverse of f(x)=(x-16)^2 is sqrt(x)+16,-sqrt(x)+16