What is the inverse of y=ln(2x-3)-ln(x+5)+1 ?

The inverse of y=ln(2x-3)-ln(x+5)+1 is (-3e-5e^x)/(e^x-2e)

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inverse of y=ln(2x-3)-ln(x+5)+1

inverse

y = ln (2 x - 3) - ln (x + 5) + 1

\frac{- 3 e - 5 e ^{x}}{e ^{x} - 2 e}

Solution steps

y = ln (2 x - 3) - ln (x + 5) + 1

Replace

x

with

y

x = ln (2 y - 3) - ln (y + 5) + 1

Solve for

y, x = ln (2 y - 3) - ln (y + 5) + 1

\frac{- 3 e - 5 e ^{x}}{e ^{x} - 2 e}

f (x) = 1 + 4 + 8 x

f (x) = \frac{1}{x ^{3}} + 4

- 2 x + 6

f (x) = \frac{4 - x}{7 - 2 x}

f (x) = (8 - 2 x)^{2}

What is the inverse of y=ln(2x-3)-ln(x+5)+1 ?
The inverse of y=ln(2x-3)-ln(x+5)+1 is (-3e-5e^x)/(e^x-2e)