What is the inverse of f(x)=(4-x)/(7-2x) ?

The inverse of f(x)=(4-x)/(7-2x) is (4-7x)/(-2x+1)

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inverse of f(x)=(4-x)/(7-2x)

inverse

f (x) = \frac{4 - x}{7 - 2 x}

\frac{4 - 7 x}{- 2 x + 1}

Solution steps

y = \frac{4 - x}{7 - 2 x}

Replace

x

with

y

x = \frac{4 - y}{7 - 2 y}

Solve for

y, x = \frac{4 - y}{7 - 2 y}

\frac{4 - 7 x}{- 2 x + 1}

f (x) = (8 - 2 x)^{2}

2^{x + 1}

y = 8 x^{2} + 6

f (x) = \frac{2 + 3 x}{x - 2}

f (x) = \frac{3}{7 + x}

What is the inverse of f(x)=(4-x)/(7-2x) ?
The inverse of f(x)=(4-x)/(7-2x) is (4-7x)/(-2x+1)