What is the inverse of y=8x^2+6 ?

The inverse of y=8x^2+6 is (sqrt(2)sqrt(x-6))/4 ,-(sqrt(2)sqrt(x-6))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=8x^2+6

inverse

y = 8 x^{2} + 6

\frac{2 x - 6}{4}, - \frac{2 x - 6}{4}

Solution steps

y = 8 x^{2} + 6

Replace

x

with

y

x = 8 y^{2} + 6

Solve for

y, x = 8 y^{2} + 6

\frac{2 x - 6}{4}, - \frac{2 x - 6}{4}

f (x) = \frac{2 + 3 x}{x - 2}

f (x) = \frac{3}{7 + x}

f (x) = 8 x - 2 x^{2}

f (x) = x + x - 1

f (x) = \frac{3}{2} cos (5 x - \frac{π}{4})

What is the inverse of y=8x^2+6 ?
The inverse of y=8x^2+6 is (sqrt(2)sqrt(x-6))/4 ,-(sqrt(2)sqrt(x-6))/4