What is the inverse of y=log_{2}((e^x+1)/4) ?

The inverse of y=log_{2}((e^x+1)/4) is ln(2^{x+2}-1)

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inverse of y=log_{2}((e^x+1)/4)

inverse

y = lo g_{2} (\frac{e ^{x} + 1}{4})

ln (2^{x + 2} - 1)

Solution steps

y = lo g_{2} (\frac{e ^{x} + 1}{4})

Replace

x

with

y

x = lo g_{2} (\frac{e ^{y} + 1}{4})

Solve for

y, x = lo g_{2} (\frac{e ^{y} + 1}{4})

ln (2^{x + 2} - 1)

f (x) = \frac{x}{4 x - 5}

f (x) = x - 1, x \geq 1

f (x) = x^{2} + 6 x + 7

\frac{1}{s + 1}

f (x) = 4 x - x, 0 \leq x \leq 1

What is the inverse of y=log_{2}((e^x+1)/4) ?
The inverse of y=log_{2}((e^x+1)/4) is ln(2^{x+2}-1)