What is the inverse of f(x)=-x+sqrt(16-x) ?

The inverse of f(x)=-x+sqrt(16-x) is (-2x-1+sqrt(4x+65))/2 ,(-2x-1-sqrt(4x+65))/2

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inverse of f(x)=-x+sqrt(16-x)

inverse

f (x) = - x + 16 - x

\frac{- 2 x - 1 + 4 x + 65}{2}, \frac{- 2 x - 1 - 4 x + 65}{2}

Solution steps

y = - x + 16 - x

Replace

x

with

y

x = - y + 16 - y

Solve for

y, x = - y + 16 - y

\frac{- 2 x - 1 + 4 x + 65}{2}, \frac{- 2 x - 1 - 4 x + 65}{2}

f (x) = 6 x^{2} + 7

\frac{4 z ^{2}}{( z - 2 ) ( 5 z + 1 )}

f (x) = 2 x^{2} - 3 x + 5

(x + 3)^{5}

What is the inverse of f(x)=-x+sqrt(16-x) ?
The inverse of f(x)=-x+sqrt(16-x) is (-2x-1+sqrt(4x+65))/2 ,(-2x-1-sqrt(4x+65))/2