What is the inverse of f(x)=-4/(3x^2)+4/3 ?

The inverse of f(x)=-4/(3x^2)+4/3 is sqrt(-4/(3x-4)),-sqrt(-4/(3x-4))

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inverse of f(x)=-4/(3x^2)+4/3

inverse

f (x) = - \frac{4}{3 x ^{2}} + \frac{4}{3}

- \frac{4}{3 x - 4}, - - \frac{4}{3 x - 4}

Solution steps

y = - \frac{4}{3 x ^{2}} + \frac{4}{3}

Replace

x

with

y

x = - \frac{4}{3 y ^{2}} + \frac{4}{3}

Solve for

y, x = - \frac{4}{3 y ^{2}} + \frac{4}{3}

- \frac{4}{3 x - 4}, - - \frac{4}{3 x - 4}

f (x) = 11 x^{3} - 8

f (x) = x^{2} - 16, x \geq 0

- 4 x + 1

f (x) = (5 - x^{3})^{\frac{1}{5}}

f (x) = \frac{2}{1 + 2 x}

What is the inverse of f(x)=-4/(3x^2)+4/3 ?
The inverse of f(x)=-4/(3x^2)+4/3 is sqrt(-4/(3x-4)),-sqrt(-4/(3x-4))