What is the inverse of f(x)=11x^3-8 ?

The inverse of f(x)=11x^3-8 is cube root of (x+8)/(11)

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inverse of f(x)=11x^3-8

inverse

f (x) = 11 x^{3} - 8

Solution steps

y = 11 x^{3} - 8

Replace

x

with

y

x = 11 y^{3} - 8

Solve for

y, x = 11 y^{3} - 8

f (x) = x^{2} - 16, x \geq 0

- 4 x + 1

f (x) = (5 - x^{3})^{\frac{1}{5}}

f (x) = \frac{2}{1 + 2 x}

f (x) = - \frac{1}{2} x^{2}

What is the inverse of f(x)=11x^3-8 ?
The inverse of f(x)=11x^3-8 is cube root of (x+8)/(11)