What is the inverse of f(x)=((x+2))/(x-1) ?

The inverse of f(x)=((x+2))/(x-1) is (2+x)/(x-1)

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inverse of f(x)=((x+2))/(x-1)

inverse

f (x) = \frac{( x + 2 )}{x - 1}

\frac{2 + x}{x - 1}

Solution steps

y = \frac{x + 2}{x - 1}

Replace

x

with

y

x = \frac{y + 2}{y - 1}

Solve for

y, x = \frac{y + 2}{y - 1}

\frac{2 + x}{x - 1}

f (x) = x^{2} + 8 x + 6300

\frac{2 x + 3}{5 x - 2}

f (x) = \frac{( 1 + e ^{x} )}{( 1 - e ^{x} )}

f (x) = 2 x + 7 + 5

f (x) = \frac{3}{x + 2} - 2

What is the inverse of f(x)=((x+2))/(x-1) ?
The inverse of f(x)=((x+2))/(x-1) is (2+x)/(x-1)