What is the inverse of f(x)=x^{0.75}+40 ?

The inverse of f(x)=x^{0.75}+40 is cube root of x^4-160x^3+9600x^2-256000x+2560000

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inverse of f(x)=x^{0.75}+40

inverse

f (x) = x^{0.75} + 40

Solution steps

y = x^{0.75} + 40

Replace

x

with

y

x = y^{0.75} + 40

Solve for

y, x = y^{0.75} + 40

f (x) = \frac{6 x}{x ^{2} - 1}

lo g_{6} (x + 2)

\frac{1}{3} lo g_{2} (x) + 1

f (x) = - x - 3 + 4

f (x) = \frac{5}{6} x + 10

What is the inverse of f(x)=x^{0.75}+40 ?
The inverse of f(x)=x^{0.75}+40 is cube root of x^4-160x^3+9600x^2-256000x+2560000