What is the inverse of f(x)=sqrt(14-x)-4,-2<= x<= 5 ?

The inverse of f(x)=sqrt(14-x)-4,-2<= x<= 5 is -x^2-8x-2

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inverse of f(x)=sqrt(14-x)-4,-2<= x<= 5

inverse

f (x) = 14 - x - 4, - 2 \leq x \leq 5

- x^{2} - 8 x - 2

Solution steps

y = 14 - x - 4

Replace

x

with

y

x = 14 - y - 4

Solve for

y, x = 14 - y - 4

- x^{2} - 8 x - 2

f (x) = e^{\frac{x}{2}}

f (x) = 2 (x - 5)^{2} - 3

f (x) = 6 15 - x - 3

\frac{2 x}{x - 2}

f (x) = \frac{x - 2}{2 x - 3}

What is the inverse of f(x)=sqrt(14-x)-4,-2<= x<= 5 ?
The inverse of f(x)=sqrt(14-x)-4,-2<= x<= 5 is -x^2-8x-2