What is the inverse of f(x)=3(x-2)^2+1 ?

The inverse of f(x)=3(x-2)^2+1 is sqrt((x-1)/3)+2,-sqrt((x-1)/3)+2

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inverse of f(x)=3(x-2)^2+1

inverse

f (x) = 3 (x - 2)^{2} + 1

\frac{x - 1}{3} + 2, - \frac{x - 1}{3} + 2

Solution steps

y = 3 (x - 2)^{2} + 1

Replace

x

with

y

x = 3 (y - 2)^{2} + 1

Solve for

y, x = 3 (y - 2)^{2} + 1

\frac{x - 1}{3} + 2, - \frac{x - 1}{3} + 2

f (x) = - \frac{1}{x - 3}

f (x) = \frac{( 3 x + 2 )}{x - 1}

f (x) = \frac{1}{2} lo g_{10} (2 x)

f (x) = \frac{2 x + 4}{5}

e^{x} - 1

What is the inverse of f(x)=3(x-2)^2+1 ?
The inverse of f(x)=3(x-2)^2+1 is sqrt((x-1)/3)+2,-sqrt((x-1)/3)+2