What is the inverse of g(x)=(x+3)^2-1 ?

The inverse of g(x)=(x+3)^2-1 is sqrt(x+1)-3,-sqrt(x+1)-3

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inverse of g(x)=(x+3)^2-1

inverse

g (x) = (x + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

Solution steps

y = (x + 3)^{2} - 1

Replace

x

with

y

x = (y + 3)^{2} - 1

Solve for

y, x = (y + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

f (x) = 5 x^{2} - 5

f (x) = 5 x^{2} - 1

f (x) = 5 x - 13

f (x) = \frac{9}{2 + x}

f (x) = - x^{2} + 6 x - 5

What is the inverse of g(x)=(x+3)^2-1 ?
The inverse of g(x)=(x+3)^2-1 is sqrt(x+1)-3,-sqrt(x+1)-3