What is the inverse of f(x)=5(x^{1/3}-6) ?

The inverse of f(x)=5(x^{1/3}-6) is (x^3}{125}+(18x^2)/(25)+\frac{108x)/5+216

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=5(x^{1/3}-6)

inverse

f (x) = 5 (x^{\frac{1}{3}} - 6)

\frac{x ^{3}}{125} + \frac{18 x ^{2}}{25} + \frac{108 x}{5} + 216

Solution steps

y = 5 (x^{\frac{1}{3}} - 6)

Replace

x

with

y

x = 5 (y^{\frac{1}{3}} - 6)

Solve for

y, x = 5 (y^{\frac{1}{3}} - 6)

\frac{x ^{3}}{125} + \frac{18 x ^{2}}{25} + \frac{108 x}{5} + 216

f (x) = - 4 x^{2} - 20 x + 16

f (x) = \frac{- 10}{1 - 4 x}

f (x) = 0.6 x - 2

f (x) = 10 0^{t}

f (x) = \frac{8 x}{x ^{2} - 1}

What is the inverse of f(x)=5(x^{1/3}-6) ?
The inverse of f(x)=5(x^{1/3}-6) is (x^3}{125}+(18x^2)/(25)+\frac{108x)/5+216